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4x^2-50x+136=0
a = 4; b = -50; c = +136;
Δ = b2-4ac
Δ = -502-4·4·136
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-18}{2*4}=\frac{32}{8} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+18}{2*4}=\frac{68}{8} =8+1/2 $
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